If it's not what You are looking for type in the equation solver your own equation and let us solve it.
-14x^2-4x+234=0
a = -14; b = -4; c = +234;
Δ = b2-4ac
Δ = -42-4·(-14)·234
Δ = 13120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{13120}=\sqrt{64*205}=\sqrt{64}*\sqrt{205}=8\sqrt{205}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-8\sqrt{205}}{2*-14}=\frac{4-8\sqrt{205}}{-28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+8\sqrt{205}}{2*-14}=\frac{4+8\sqrt{205}}{-28} $
| 6x-2+3x=20x-40 | | 80=20t-5t^2 | | -4(x+6)-12=48 | | 7(d-1)=56 | | 7(2x+1)-3x=62 | | 2(7x+4)-4(8x-3)=0 | | 11m-(6m-5)=28 | | z+3z+8=-4 | | 6x-2+3=20x-40 | | .005x^2-0.3x-4=25 | | 5(x-3)+3(-2x+2)=0 | | 5x=3x-27 | | 2(2x+4)-3(x-1)=16 | | x+20+130+x+40=180 | | 1=-3(-1)+b | | 8a/9=24 | | (2x-1)=-2(3x+4) | | 10x+5=x-40 | | -(4x+4)=0 | | 4(x-3)-2x=x-10 | | 8x+4=2x-13 | | 24+p=12+2p | | 3x-4+9+-2=54 | | 7^-5y=8 | | 4x^+5-12x=0 | | 3+4d-14=15-5d=4d | | 10x+22=8x−4. | | x+3(-x-50)+2x+30=180 | | 3.64÷1.4=e | | 85.6=8(m+3.9) | | 105+(14x-9)=180 | | 7.5d=2. |